4by12

Complex Square Root

February 14, 2008 – 1:45 am

Proof that 1 = -1:

$\frac{1}{\sqrt{i}} = \sqrt{\frac{1}{i}} = \sqrt{-i} = \sqrt{-1} \sqrt{i} = i \sqrt{i}$
$\Rightarrow 1 = i \sqrt{i} \sqrt{i} = i^2 = -1$

This function should be taken outside and shot.