Complex Square Root
Thursday, February 14th, 2008Proof that 1 = -1: [tex] \frac{1}{\sqrt{i}} = \sqrt{\frac{1}{i}} = \sqrt{-i} = \sqrt{-1} \sqrt{i} = i \sqrt{i}[/tex] [tex] \Rightarrow 1 = i \sqrt{i} \sqrt{i} = i^2 = -1 [/tex] This function should be taken outside and shot.
Subscribe by email